如何用js根据开始时间和结束时间获取每个时间点

来源：化陀汽车网
本篇博客实现效果（内附demo地址）:
test.html文件代码
<html lang="en">
<head>
 <meta charset="UTF-8">
 <title>Title</title>
 <script src="./js/jquery-2.1.1.js"></script></head><body><p class="getDay"><a href="#">获取2017-08-28到2017-09-08该段时间内的所有以天为单位的日期</a></p><p class="getWeek"><a href="#">获取2017-06-05到2017-09-04该段时间内的所有以周一为单位的日期</a></p><p class="month"><a href="#">获取2016-06-01到2017-09-01该段时间内的所有以月为单位的日期</a></p><p class="year"><a href="#">获取2003-01-01到2017-01-01该段时间内的所有以年为单位的日期</a></p></body><script>

 $(document).ready(function () {
 $(".getDay").click(function () {
 alert(getDayAll("2017-08-28","2017-09-08"));
 })
 $(".getWeek").click(function () {
 alert(getWeekAll("2017-06-05","2017-09-04"));
 })
 $(".month").click(function () {
 alert(getMonthAll("2016-06-01","2017-09-01"));
 })
 $(".year").click(function () {
 alert(getYearAll("2003-01-0","2017-01-01"));
 })
 }) Date.prototype.format=function (){
 var s='';
 s+=this.getFullYear()+'-'; // 获取年份。
 s+=(this.getMonth()+1)+"-"; // 获取月份。
 s+= this.getDate(); // 获取日。
 return(s); // 返回日期。
 }; //按日查询
 function getDayAll(begin,end){
 var dateAllArr = new Array(); 
 var ab = begin.split("-"); 
 var ae = end.split("-"); 
 var db = new Date();
 db.setUTCFullYear(ab[0], ab[1]-1, ab[2]); 
 var de = new Date();
 de.setUTCFullYear(ae[0], ae[1]-1, ae[2]); 
 var unixDb=db.getTime(); 
 var unixDe=de.getTime(); 
 for(var k=unixDb;k<=unixDe;){
 dateAllArr.push((new Date(parseInt(k))).format().toString());
 k=k+24*60*60*1000;
 } return dateAllArr;
 } //按周查询
 function getWeekAll(begin,end){
 var dateAllArr = new Array(); 
 var ab = begin.split("-"); 
 var ae = end.split("-"); 
 var db = new Date();
 db.setUTCFullYear(ab[0], ab[1]-1, ab[2]); 
 var de = new Date();
 de.setUTCFullYear(ae[0], ae[1]-1, ae[2]); 
 var unixDb=db.getTime(); 
 var unixDe=de.getTime(); 
 for(var k=unixDb;k<=unixDe;){
 dateAllArr.push((new Date(parseInt(k))).format().toString());
 k=k+7*24*60*60*1000;
 } return dateAllArr;
 } function getMonthAll(begin,end) {
 var d1 = begin; 
 var d2 = end; 
 var dateArry = new Array(); 
 var s1 = d1.split("-"); 
 var s2 = d2.split("-"); 
 var mCount = 0; 
 if (parseInt(s1[0]) < parseInt(s2[0])) {
 mCount = (parseInt(s2[0]) - parseInt(s1[0])) * 12 + parseInt(s2[1]) - parseInt(s1[1])+1;
 } else {
 mCount = parseInt(s2[1]) - parseInt(s1[1])+1;
 } if (mCount > 0) { 
 var startM = parseInt(s1[1]); 
 var startY = parseInt(s1[0]); 
 for (var i = 0; i < mCount; i++) { 
 if (startM < 12) {
 dateArry[i] = startY + "-" + (startM>9 ? startM : "0" + startM);
 startM += 1;
 } else {
 dateArry[i] = startY + "-" + (startM > 9 ? startM : "0" + startM);
 startM = 1;
 startY += 1;
 }
 }
 } 
 return dateArry;
 } 
 function getYearAll(begin,end) {
 var d1 = begin; 
 var d2 = end; 
 var dateArry = new Array(); 
 var s1 = d1.split("-"); 
 var s2 = d2.split("-"); 
 var mYearCount = parseInt(s2[0]) - parseInt(s1[0])+1; 
 var startY = parseInt(s1[0]); 
 for (var i = 0; i < mYearCount;i++) {
 dateArry[i] = startY;
 startY += 1;
 } 
 return dateArry;
 }
 </script>
 </html>